Prove that ab³÷ac³=a^((b-c) (b+c)²-bc³)
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Answer:
Let's solve your equation step-by-step.
ab3
a
c3=a(b−c)((b+c)2)−bc3
b3c3=a−bc3+b3+b2c−bc2−c3
Step-by-step explanation:
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