Prove that ABCD is a parallelogram
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Step-by-step explanation:
GIVEN: E is mid point of DC
ABCD IS A PARALLELOGRAM
AE bisects angle A
BE bisects angle B
In triangle ABE
Angle EBA= Angle EBC ...........[i]
(BE bisects angle B)
Angle EBA =Angle BEC .........[ii]
(V.OA)
In triangle BEC
Angle EBC =Angle BEC (from [i] and [ii] )
therefore,BC =EC
(sides opposite to equal angles are equal)
BC =1/2 CD (SINCE E is the mid point)
2BC =CD
AB =2BC
(AB=CD , Opposite side of parallelogram are equal)
Hence proved
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