Question

Prove that Ac2=Ab2+bc2 if angle b =90degree

Answer 1

this is whole theorem and it is neatly proved

Answer 2

Answer:

$AC^2=AB^2+BC^2$

Step-by-step explanation:

Given information: In triangle ABC, ∠B=90°.

To prove: $AC^2=AB^2+BC^2$

Proof:

According to the Pythagoras theorem, in a right angled triangle

$hypotenuse^2=perpendicular^2+base^2$

Since ∠B=90°, it means ABC is right angled triangle, AC is hypotenuse, AB and BC are two legs.

Using Pythagoras theorem we get

$AC^2=AB^2+BC^2$

Hence proved.