prove that an angle in a semicircular in 90 degree
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Here is ur answer... see the above pics..
in the first pic . given is there.. in second pic.. proof is there..
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in the first pic . given is there.. in second pic.. proof is there..
pls mark as brainliest and plz follow me
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Consider a circle with a cyclic triangle in a semicircle.
Let it be tri ABC,
with BC as the diameter
Now we know angle subtained by an arc at the centre is twice the angle subtained by it in the opp segment
By this angle subtained by the arc BAC
angle BOC=1/2 angle BAC
But angle BOC=180°
angle BAC=90°
Therefore angle in semicircle is 180°
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