prove that Angele inscribed in semi circle is right
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Suppose that ACB in the coordinate plane is inscribed in a semicircle; in other words, if X is the midpoint of the segment [AB] then all three points A, B, C are equidistant from X. Then ACB is a right angle. r = |a − x| = |b − x| = |c − x| .
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The intercepted arc for an angle inscribed in a semi-circle is 180 degrees. Therefore the measure of the angle must be half of 180, or 90 degrees. In other words, the angle is a right angle.
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