Math, asked by farha78624, 1 year ago

prove that angle opposite to equal side of an isosceles triangle are equal


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Answers

Answered by Anonymous
2
Given,
ABC is an isosceles triangle
and
AB = AC

To prove : Angle B = Angle C

In triangle ABD and triangle ACD,

i) AB=AC(given)
ii) AD = AD (Common median)
iii)Angle BAD = Angle CAD (Commom angles)

Therefore,
Triangle ABD congruent to Traingle ACD(SAS)

Therefore,
Angle B = Angle C ( CPCT){Proved}



Sorry for not able to provide the figure due to slow network...but I hope you can figure it out...


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