prove that angle opposite to equal side of an isosceles triangle are equal
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Given,
ABC is an isosceles triangle
and
AB = AC
To prove : Angle B = Angle C
In triangle ABD and triangle ACD,
i) AB=AC(given)
ii) AD = AD (Common median)
iii)Angle BAD = Angle CAD (Commom angles)
Therefore,
Triangle ABD congruent to Traingle ACD(SAS)
Therefore,
Angle B = Angle C ( CPCT){Proved}
Sorry for not able to provide the figure due to slow network...but I hope you can figure it out...
Mark as brainliest if you like it.
ABC is an isosceles triangle
and
AB = AC
To prove : Angle B = Angle C
In triangle ABD and triangle ACD,
i) AB=AC(given)
ii) AD = AD (Common median)
iii)Angle BAD = Angle CAD (Commom angles)
Therefore,
Triangle ABD congruent to Traingle ACD(SAS)
Therefore,
Angle B = Angle C ( CPCT){Proved}
Sorry for not able to provide the figure due to slow network...but I hope you can figure it out...
Mark as brainliest if you like it.
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