Math, asked by prashil707, 1 year ago

Prove that anglee opposite to equal sides of an isosceles triangle are equal

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Answered by harditmaan1
0

Answer:Sahil7à Ambitious

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

Hence proved that angles opposite to equal sides of a triangle are equal.

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