Question

prove that angles opposite to equal side of a triangle are equal ​

Answer 1

hey mate here is your answer

Answer 2

Answer

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This is known as Isosceles triangle theorem

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ABC is a given triangle with, AB=AC.

To prove: Angle opposite to AB= Angle

opposite to AC (i.e) ∠C=∠B

Construction: Draw AD perpendicular to BC

∴∠ADB=∠ADC=90⁰

Proof:

Consider △ABD and △ACD

AD is common

AB=AC

∴∠ADB=∠ADC=90⁰

Hence ∠ABD=∠ACD

∠ABC=∠ACB

∠B=∠C. Hence proved ✅

This is known as Isosceles triangle theorem