Question

prove that angles opposite to equal sides of a triangle are equal step by step

Answer 1

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AD bisector of angle A meeting BC at D.

In ∆ABD and ∆ACD

1.AD=AD[common]

2.AB=AC[given]

3.<BAD=<CAD[by construction]

Therefore, ∆ABD & ∆ACD are congruent [S.A.S]

This implies, <ABD=<ACD[C.P.C.T]

Hence, it is proven that angles opposite to equal sides of a triangle are equal.

Hope this helps you

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