Question

prove that angles opposite to equal sides of an isosceles triangle are equal????
fast answer it plzz​

Answer 1

Answer:

Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D

Now in triangles ABD and ACD We have AB=AC (Given)

∠BAD=∠CAD (because AD is bisector of ∠A

AD=AD (Common side)

Therefore by SAS congruence condition we have

△ABC≅△ACD

⇒∠B=∠C

(Corresponding parts of congruent triangles are equal )

Answer 2

Answer:

option 2 is the correct answer

Step-by-step explanation:

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