prove that angles opposite to the equal side of a triangle are equal
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Let there be an isosceles triangle abc.(two sides of an isosceles triangle are equal).
Now draw a perpendicular from a on bc.
In triangle abd and triangle acd we have,
ad=da(equal),
angle adb= angle adc(90 degree).
ab=ac(abc is an isosceles triangle.)
Therefore triangle abd congruent triangle acd.(rhs)
Therefore angle abc= angle acd (cpct) (proved).
Now draw a perpendicular from a on bc.
In triangle abd and triangle acd we have,
ad=da(equal),
angle adb= angle adc(90 degree).
ab=ac(abc is an isosceles triangle.)
Therefore triangle abd congruent triangle acd.(rhs)
Therefore angle abc= angle acd (cpct) (proved).
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