Math, asked by thasvan235, 8 months ago

prove that any odd positive integer is form 8q+1 8q+3 8q+5 8q+7

Answers

Answered by keshav1115
2

Answer:

here's explanation with details..

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Answered by sipon
3

Answer:

using :

a = bq+r where, 0 <= r < b

so all possible values of a if b = 8

a = 8q+0, 8q+1, 8q+2, 8q+3, 8q+4, 8q+5, 8q+6, 8q+7

as it is asked for all odd values:

8q+0, 8q+2, 8q+4, 8q+6 will not be included as all these are even values

so answer will be:

a = 8q+1, 8q+3, 8q+5, 8q+7

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