Question

While writing all the numbers from 700 to 1000,how many numbers occur in witch the digit At hundred s place Is great than the tens place,and the digit is tens place is greater than the digit at unit s place?

Answer 1

||✪✪ QUESTION ✪✪||

While writing all the numbers from 700 to 1000,how many numbers occur in witch the digit At hundred s place Is great than the tens place,and the digit is tens place is greater than the digit at unit s place ? ( Excellent Question).

|| ✰✰ ANSWER ✰✰ ||

we know that, numbers from 700 to 1000, the digit at hundred's place can be 7, 8 or 9. So, we have 3 Possibility here ..

Now, for the digit at ten's place to be greater than the digit at unit's place, total numbers is equal to the value of ten's digit.

Example :-

→ for 4 at ten's digit, numbers can be = 40, 41 , 42 and 43 = Total 4.

Similarly,

→ for 6 at ten's digit, numbers can be = 60, 61, 62, 63, 64, and 65 = Total 6 .

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So,

From 700 to 800, The first number is 7, so Total Numbers are = 6 + 5 + 4 + 3 + 2 + 1 = 21

From 801 to 900, The first number is 8, so Total Numbers are = 7 + 6 + 5 + 4 + 3 + 2 + 1 = 28

From 901 to 1000, The first number is 8, so Total Numbers are = 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 36

So,

→ Total Numbers = 21 + 28 + 36 = 85

Hence, There are 85 Total Numbers satisfy The given Condition..

Answer 2

$\huge\mathbb{\underline{QUESTION:-}}$

While writing all the numbers from 700 to 1000,how many numbers occur in witch the digit At hundred s place Is great than the tens place,and the digit is tens place is greater than the digit at unit s place ?

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$\huge\mathbb{\underline{SOLUTION:-}}$

Now for the digit at ten's place is greater than the digit at unit's place, total numbers is equal to value of ten's place. For 3 at ten's place numbers can be 30, 31.

In the same way for 5 at ten's place numbers can be 50, 51, 52, 53, 54, 55 (6 numbers)

• From 700 to 800, the first number is 7, so we get

• 6 + 5 + 4 + 3 + 2 + 1 = 21 numbers

• From 801 to 900, he first number is 8, so we get

• 7 + 6 + 5 + 4 + 3 + 2 + 1 = 28 numbers

• From 901 to 1000, he first number is 8, so we get

• 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 36 numbers

Adding all the numbers we get the total as

21 + 28 + 36 = 85 numbers .

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