Question

Prove that any point on the bisector of an angle is equidistant from
the arms of the angle.
[Hint: Take any point P on bisector BD of ZABC. Draw PM I on AB and
PN I BC. Then prove APBM=APBN (by ASA criterion of congruence).
At last, prove PM PN (as corresponding parts of congruent triangles
are equal)]
N
May
0,01
ABCD is a square and ac in​

Answer 1

Answer:

what you SAID it was not CLEAR

Answer 2

Prove that any point on the bisector of an angle is equidistant from

the arms of the angle.

[Hint: Take any point P on bisector BD of ZABC. Draw PM I on AB and

PN I BC. Then prove APBM=APBN (by ASA criterion of congruence).

At last, prove PM PN (as corresponding parts of congruent triangles

are equal)]

N

May

0,01

ABCD is a square and ac in

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