prove that any two of the triangles formed by the diagnol of a square are congruent
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Step-by-step explanation:
We can prove that any two of the adjacent triangles formed by the intersecting diagonals are congruent. ... Combining these two, we see that since the diagonals bisect each other, they form medians in the isosceles triangle ΔABC, and are thus perpendicular.
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Answer:
Let ABCD be the square and line AC be its diagonal. We know, in a square all sides are equal and all the angles are right angled.
So, in ABC and ACD,
AB=CD
angle ABC= angle ACD
AD=BC
So, by SAS congurency both the triangles are equal.
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