Math, asked by Mouzin, 1 year ago

Prove that anything raised to power 0 is equal to 1?
 {x}^{0}  = 1

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Answered by Uzma2002
2
to prove that x^0=1

we know that
x root0 = x \times x
(0 times)


we know that 1 -1 =0
hence,
we can say that
x^0= x ^ 1 - 1
Now we got that x^0= (x ^1 ) X (x ^ - 1)
x^0= x^1 X 1/ x^1

where x^1 and x^1 gets cancelled

therefore x^0 = 1

proved


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Answered by Anonymous
0

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Hope it helps you friend.

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