Question

prove that AP bisect angle angle BAC.

Answer 1

Given,
PN=PM
angle PNA= angle PMA
Now,
In ∆PAN & ∆PAM we have:-
PN = PM [ Given]
angle PNA = angle PMA [ Given]
PA = PA [ Common]
So,
∆PAN congruent ∆ PMA
So,
angle PAN = angle PAM [ C.P.C.T]
So,
PA bisects angle BAC

Hope this helps you!

Answer 2

#hope it helps...^_^