Question

prove that ar(AOD) = ar(BOC)

Answer 1

it can be observed that ∆ DAC and ∆DBC lie on the same base DCand between the same parallel AB and CD .

area(∆ DAC) = area (∆DBC)
area (∆DAC) - area(∆DOC )= area
(∆DBC)- area (∆DOC)
area (∆ AOD ) = area ( ∆BOC)


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Answer 2

In the trapezium AB is parallel to DC.
Therefore triangles between the same parallels and same base have the same area.
So triangle abd and abc will have same area.
We will subtract aob as it is common in both.
So area of aod = area of boc
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