Prove that÷
Area of a Triangle=√s(s-a)(s-b)(s-c)
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Answer:
Step-by-step explanation:
herons formula it come in standard 9
Perimeter of the triangle ABC is (a+b+c)/2
Area of triangle ABC = ½ (ah) → (1)
Now we have find h in terms of a, b and c.
In right ΔADB, c2 = p2 + h2
In right ΔADC, b2 = q2 + h2
Here q = a – p
⇒ q2 = (a – p)2
= a2 – 2ap + p2
⇒ q2 + h2 = a2 – 2ap + p2 + h2
⇒ b2 = a2 + h2 – 2ap + p2
⇒ b2 = c2 – 2ap + p2
Solve this equation for p and substitute in equation (1) to get area of triangle formula.
sulabh0701:
prove it
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