Prove that area of a triangle whose vertics are A(x,x-2) , B(x+23,x+2)andC(x+3,x) is idependent of x.
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A(x,x-2) , B(x+23,x+2) and C(x+3,x)
The area of the triangle is
1/2[x(x+2-x)+(x+23)(x-(x-2))+(x+3)(x-2-(x+2))]
=1/2[2x+2x+46-4x-12]
=1/2(34)=17 sq.cm
Therefore the area of the triangle is 17 sq.cm and Hence the area is independent of x
Hope it helped you!! :)
The area of the triangle is
1/2[x(x+2-x)+(x+23)(x-(x-2))+(x+3)(x-2-(x+2))]
=1/2[2x+2x+46-4x-12]
=1/2(34)=17 sq.cm
Therefore the area of the triangle is 17 sq.cm and Hence the area is independent of x
Hope it helped you!! :)
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