Question

prove that area of rhombus = 1/2•product of the diagonal

Answer 1

The  two diagonals of a rhombus are perpendicular by rule and also bisect each other. One diagonal divides the rhombus into two identical triangles with that diagonal being the base of both triangle's and half the other diagonal being the height of each.

Let the diagonals be d1 and d2. So the area of the rhombus (using one half base times height) becomes twice the area of one of the triangles.

B=base

H=height

A = 2 ( 1/2 BH) where B = d1 and H = 1/2 d2  

A = 2 ( 1/2 d1 * 1/2 d2 ) = 1/2 d1*d2

Hence it is proved.

Hope it helps.

Answer 2

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hope helped!!
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