prove that area of the sector of angle theta is equal to theta upon 360 into Pi R Square
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Area of circle = πr^2
Area of 360° sector = πr^2
Area of ∅° sector = πr^2/360 ×∅
Or it can be written as
∅/360 × πr^2
Area of 360° sector = πr^2
Area of ∅° sector = πr^2/360 ×∅
Or it can be written as
∅/360 × πr^2
ashasharma1975:
thanks
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Answer:
Step-by-step explanation:
So if the central angle made by the sector is θ degrees then the area should be (θ/360)(πr^2)
In radian measure the length l of the arc is given by l = rθ where θ is measured in radians (π radians = 180 degrees)
In radian measure, the area A of sector of a circle is given by A = 1/2 r^2 θ = 1/2 r rθ = 1/2 rl.
Hence the area of a sector is (θ/360)(πr^2) in degree measure and is = 1/2 rl in radian measure.
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