Prove that-
(AxB) = (BxA) iff A=0(phi) B=0(phi) or A=B
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phiphi
a:b phi(a) phi(b)
a:b phi(a) phi(b)
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Step-by-step explanation:
If A = B then substituting B for A gives A × B = A × A = B × A. If A = ∅ or B = ∅,
Then by Proposition " If A is a set, then A × ∅ = ∅ and ∅ × A = ∅
We get
A × B = ∅ = B × A.
Suppose that A and B are non-empty sets and A × B = B × A. Let x ∈ A. Since
B = ∅, there exists an element y ∈ B, so that (x, y) ∈ A × B. Since A × B = B × A, we
have that ( x , y ) ∈ B × A . By the definition of Cartesian product, x ∈ B. Therefore,
A ⊆ B. Similarly B ⊆ A. Thus, A = B.
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