Question

prove that axbxc= a.(cb)-a.(b-c)​

Answer 1

Step-by-step explanation:

B×CB×C is a vector purpendicular to the plane formed by BB and CC. Hence the vector A×(B×C)A×(B×C) lies in the plane formed by BB and CC.

So we can write A×(B×C)A×(B×C) as,

A×(B×C)=A×(B×C)=αB−βCαB−βC ⋯†⋯†

Multiply(dot product) †† by AA to get,

A.(A×(B×C))=A.(A×(B×C))=α(A.B)−β(A.C)α(A.B)−β(A.C)

Since

A.(A×(B×C))=A.(A×(B×C))=(A×A).(B×C)=0(A×A).(B×C)=0

We get α(A.B)−β(A.C)=0α(A.B)−β(A.C)=0

α

Answer 2

Answer:

hence why the rooi

Step-by-step explanation:

go to need to need to be there by me and I hope that you going out tonight or 9 lesson for me to get a good afternoon and your family are in our thoughts and I have a good friend and I are well with me kijiyega the year and model the