prove that bd=bc ......plzzzzzzz
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Answered by
4
Hey !
Here is ur answer.....
1. AB =AC (Given)
B =Angle C (Angles on the opposite equal sides of triangle are equal )
2.. In ABD and ADC
AB=AC (Given)
Angle 1 = Angle 2 (given)
AC =AC (common)
By SAS criteria, ABD is congruent ADC
By CPCT , BD = DC
3.. By CPCT, Angle ADB =Angle ADC ------- a
ADB +ADC =180° (linear pair)
ADB +ADB = 180° ( From a )
2(ADB) =180°
ADB =180/2
ADB = 90°
ADB=ADC=90°
#Hence Proved !!
Here is ur answer.....
1. AB =AC (Given)
B =Angle C (Angles on the opposite equal sides of triangle are equal )
2.. In ABD and ADC
AB=AC (Given)
Angle 1 = Angle 2 (given)
AC =AC (common)
By SAS criteria, ABD is congruent ADC
By CPCT , BD = DC
3.. By CPCT, Angle ADB =Angle ADC ------- a
ADB +ADC =180° (linear pair)
ADB +ADB = 180° ( From a )
2(ADB) =180°
ADB =180/2
ADB = 90°
ADB=ADC=90°
#Hence Proved !!
Answered by
2
In ABD and ABC
AB = AC (given)
angle 1 = angle 2 (given)
AD = AD (common)
By side- angle-Side , ABD is congruent to ABC
thus by CPCT, bd= bc.
AB = AC (given)
angle 1 = angle 2 (given)
AD = AD (common)
By side- angle-Side , ABD is congruent to ABC
thus by CPCT, bd= bc.
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