prove that c0+c1+c2------+cn=2n
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Related Questions (More Answers Below). How do I prove that C1^2-2C2^2+3C3^2-… +(-1) ^n Cn^2 is equal to ((-1) ^ ((n/2)-1)) (n/2) (n!
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(1+x)^n=C0+C1x+C2x^2+ ----------- +Cn x^n
put x=1
(1+1)^n=C0+C1+C2+ ----------+Cn
C0+C1+C2+ ---------- +Cn =2^n
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