prove that cos (π/12)-sin(π/12)=1/√2
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Answered by
24
Hey there !
Solution:
We know that,
360 = 2π
=> π = 360 / 2 = 180°
According to the Question,
Cos ( π / 12 ) - Sin ( π / 12 ) = 1 / √2
Taking the Left Hand Side into consideration we get,
=> Cos ( 180 / 12 ) - Sin ( 180 / 12 )
=> Cos ( 15 ) - Sin ( 15 )
Let us simplify the above equation. We get,
=> Sin ( 90 - 15 ) - Sin 15 )
=> Sin 75 - Sin 15
We know that,
Sin C - Sin D = 2 Cos [ ( A + B ) / 2 ] . Sin [ ( A - B ) / 2 ]
=> Sin 75 - Sin 15 = 2 Cos ( 75 + 15 ) / 2 . Sin ( 75 - 15 ) / 2
=> Sin 75 - Sin 15 = 2 Cos 90 / 2 . Sin 60 / 2
=> Sin 75 + Sin 15 = 2 Cos 45 . Sin 30
=> Sin 75 - Sin 15 = 2 × 1 / √2 × 1 / 2
=> Sin 75 - Sin 15 = 1 / √2.
Hence Proved !
Hope my answer helped !
Steph0303:
:-)
Answered by
19
Answer is as follows
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