Prove that cos 20 + cos 100 +cos 140 = 0
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Answered by
4
Answer:
Step-by-step explanation:
cos20∘+cos100∘=cos(60∘−40∘)+cos(60∘+40∘)=cos40∘
by using the addition formulae for cos.
Then cos140∘=cos(180∘−40∘)=−cos(40∘). So
cos20∘+cos100∘+cos140∘=cos40∘−cos40∘=0
Answered by
1
by using two times cos(C)+cos(d)
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