prove that cos^2thita + tan ^2thta - 1 /sin^2thta = tan ^2thita
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Answer:
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Answer:
Given (cos
2
θ−sin
2
θ)=tan
2
ϕ
To prove:
cosϕ=
2
cosθ
1
(cos
2
θ−sin
2
θ)=tan
2
ϕ
add 1 on both sides
(cos
2
θ−sin
2
θ)=tan
2
ϕ+1
cos
2
+(1−sinθ)=(1+tan
2
ϕ)
cos
1
θ+cos
2
θ=sec
2
ϕ
⇒ 2cos
2
θ=sec
2
ϕ
⇒ 2cos
2
θcos
2
ϕ=1
⇒ cos
2
ϕ=
2cos
1
θ
1
⇒ cosθ=
2
cosθ
1
Step-by-step explanation:
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