Prove that Cos^4A-Sin^4A+1=2Cos^2A
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I learned this from a friend. Hope it helps
Step-by-step explanation:
First, group the first two terms and factor it.
(cos^4A-sin^4A)+1=2cos^2A
(cos^2A-sin^2A)(cos^2A+sin^2A)+1=2cos^2A
Then, apply the Pythagorean identity which is cos^2theta + sin^2theta=1 .
(cos^2A-sin^2A)(1)+1=2cos^2A
cos^2A-sin^2A + 1=2cos^2A
Then, group the second and last term at the left side of the equation.
cos^2A+(-sin^2A+1)=2cos^2A
cos^2A+(1-sin^2A)=2cos^2A
To simplify the expression inside the parenthesis, apply the Pythagorean identity again.
cos^2A+cos^2A=2cos^2A
2cos^2A=2cos^2A
Since left side simplifies to 2cos^2A which is the same term with the right side, hence it proves that the given equation is an identity.
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