Question

Prove that cos (60° - A) cos(30°- B)- sin (60° - A) sin (30°-B) = sin (A+B)..​

Answer 1

Answer:

$0.000000000000085$

Answer 2

Answer:

using identity

cosAcosB-sinAsinB = cos(A+B)

=>cos(60-A)cos(30-B)-sin(60-A)sin(30-B) =>cos(60-A+30-B) = cos(90-(A+B)) = sin(A+B)=RHS hence proved

Step-by-step explanation:

[cos(90-A) = sinA]