Question

Prove that
Cos 6theta= 32 cos ^6 theta-48 cos^4 theta + 18cos ^2 thata-1​

Answer 1

Answer:Using,

cos2x=2cos  

2

x−1

cos3x=4cos  

3

x−3cosx

LHS:

cos6x=2cos  

2

3x−1

=2(4cos  

3

x−3cosx)  

2

−1

=2(16cos  

6

x+9cos  

2

x−24cos  

4

x)−1

=32cos  

6

x−48cos  

4

x+18cos  

2

x−1 = RHS

Step-by-step explanation: