Math, asked by murshidalbimaany, 7 months ago

prove that :cos 6x=1-2sin^23x

Answers

Answered by mathdude500

Step-by-step explanation:

$cos6x \: = cos(3x + 3x) \\ = cos3x.cos3x - sin3x.sin3x \\ = {cos}^{2} 3x - {sin}^{2} 3x \\ = 1 - {sin}^{2} 3x - {sin}^{2} 3x \\ = 1 - 2 {sin}^{2} 3x \\$

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prove that :cos 6x=1-2sin^23x​

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prove that :cos 6x=1-2sin^23x