Math, asked by u8uygy, 9 months ago

Prove that: cos(90- L+sin(90°-0) + 1 + sin(90-0) = 2coseco . Cos(90°-o) conexe 29 and 40 area co

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Answered by Anonymous

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Answer:

cos(90- L+sin(90°-0) + 1 + sin(90-0) = 2coseco . Cos(90°-o) conexe 29 and 40 area co

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Answered by Anonymous

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