Prove that:cos cube theta+sin cube theta÷cos theta+sin theta + cos cube theta-sin cube theta÷cos theta-sin theta=2
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Take LCM and multiply,
then cancel the like terms,
you will get simplified form,
then use difference of squares,
then again cancel the terms,
then make sin^2theta +cos^2theta = 1
you will get your answer...
then cancel the like terms,
you will get simplified form,
then use difference of squares,
then again cancel the terms,
then make sin^2theta +cos^2theta = 1
you will get your answer...
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