Math, asked by hemudas6094, 11 months ago

Prove that cos1°cos2°cos3°------------cos90°-------cos180°=0

Answers

Answered by Anonymous
6

Answer :-

→ = 0 .

 \huge \orange{ \mid{ \underline{ \overline{ \sf Explanation :- }} \mid}

We have ,

°•° cos 1° cos 2° cos 3° ..... cos 180° .

[ We can write this as :- ]

= cos 1° cos 2° cos 3° ..... cos 89° cos 90° cos 91° ...... cos 180° .

[ In between them, There is cos 90 ° .]

[ And, we know that , the value of cos 90° = 0 . ]

= cos 1° cos 2° cos 3° ..... cos 89° × 0 × cos 91° ...... cos 180° .

[ And, If any number is multiplied by 0 , then the result is 0 ] .

 \huge \boxed{ \boxed{ \green{\underline{ \underline{ \sf = 0.}}}}}

✔✔ Hence, it is solved ✅✅.

Answered by pewschooler09
0

Answer:

▶ Answer :-

→ = 0 .

We have ,

°•° cos 1° cos 2° cos 3° ..... cos 180° .

[ We can write this as :- ]

= cos 1° cos 2° cos 3° ..... cos 89° cos 90° cos 91° ...... cos 180° .

[ In between them, There is cos 90 ° .]

[ And, we know that , the value of cos 90° = 0 . ]

= cos 1° cos 2° cos 3° ..... cos 89° × 0 × cos 91° ...... cos 180° .

[ And, If any number is multiplied by 0 , then the result is 0 ] .

✔✔ Hence, it is solved ✅✅.

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