prove that cos2 A + sin2 A = 1
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TO PROVE:
sin²A + cos²A = 1
PROOF:
Consider right △ ABC, where ∠B = 90⁰
a,b and c are side of the triangle ABC,
Sin A = Opposite side/ Hypotenuse
∴ Sin A = a/b ------- (1)
Cos θ = Adjacent side/Hypotenuse
∴ Cos A = c/b ------- (2)
By Pythagoras theorem, in △ ABC
Base² + Altitude² = Hypotenuse²
==> a² + c² = b²
• Now, divide the whole equation by b²
==> a²/b² + c²/b² = b²/b²
==> (a/b)² + (c/b)² = 1
• Substituting equations (1) and (2),
==> Sin²A + Cos²A = 1
Hence, proved ✅
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