Prove that cos2θ
sin θ
+ sin θ = cosec θ .
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Step-by-step explanation:
LHS= (cos2θ-sinθcosecθ+sin2θ)/sinθ =
(cos2θ+sin2θ-1)/sinθ [Therefore sinθcosecθ=1]
=0
=LHS =RHS
Hence proved.
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