Prove that cos20*cos40*cos60*cos80=1/6
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cos20cos40cos60cos80=1/6
multiply both sides by sin20
sin20cos20cos40cos60cos80=asin20
By double angle formula,
#sin20cos20=1/2sin40
We can continue this pattern.
1/2sin40cos40cos60cos80=asin20
1/4sin80cos80cos60=asin20
1/8sin160cos60=asin20
cos60 is simply 1/2
So,
1/16sin160=asin20
However,
sin160=sin20
So, a=1/16
multiply both sides by sin20
sin20cos20cos40cos60cos80=asin20
By double angle formula,
#sin20cos20=1/2sin40
We can continue this pattern.
1/2sin40cos40cos60cos80=asin20
1/4sin80cos80cos60=asin20
1/8sin160cos60=asin20
cos60 is simply 1/2
So,
1/16sin160=asin20
However,
sin160=sin20
So, a=1/16
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DEAR STUDENT,
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
Kindly check the attached papers for a detailed solution along with step by step elaboration to reach our final solution that is our final desired or required answer to this query that is completely proved.
Which is the required proof or solution process for this type of query.
Hope this helps you and solves your doubts for applying trigonometric identifies to reach a proper solution or a proof!!!!!
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