prove that cos²72°-sin²54=-√5/4
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Answer:
ANSWER
cos²72 = cos²(90 - 18) = sin²18
sin²54 = sin²(90 - 36) = cos²36
Firstly find out the value of sin(18°) using the compound angle formulae as shown.
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Step-by-step explanation:
Let us consider the LHS
sin2 42° – cos2 78° = sin2 (90° – 48°) – cos2 (90° – 12°)
= cos2 48° – sin2 12° [since, sin (90 – A) = cos A and cos (90 – A) = sin A]
As we know, cos (A + B) cos (A – B) = cos2A – sin2B
Now the above equation becomes,
= cos2 (48° + 12°) cos (48° – 12°)
= cos 60° cos 36° [since, cos 36° = (√5 + 1)/4]
= 1/2 × (√5 + 1)/4
= (√5 + 1)/8
= RHS
Thus proved.
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