Prove that cos36*cos72 = 1/2
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try looking into the standard angles tables
Hxxeemmm:
But you're supposed to prove it without looking into the value of the respective cosine of the angles
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Step-by-step explanation:
cos36 - cos72
cos36-cos72= (cos²36-cos²72)/cos36
so from identity cos²x=(cos2x+1)/2
so cos36-cos72=cos72+1-(cos144+1)/2(cos36+cos72
which is equal to 1/2
or using
cos36-cos72=cos36-cos2(36)
and from identity cos2x=2cos²x-1
so cos36-cos72=cos36-(2cos²36-1)=cos36-2cos²36+1
and we know cos36 to be (√5 + 1)/4
so cos36-cos72=(√5 + 1)/4 - 2((√5 + 1)/4)² +1
which is equal to (√5 + 1)/4 - 2((5 + 2√5 + 1)/16)) + 1
which is equal to (√5 + 1)/4 -2(2(3 + √5)/16)) + 1
so equals (√5 + 1)/4 - ((3 + √5)/4)) + 1
which is equal to (√5 + 1 -3 - √5 + 4)/4
which is equal to 2/4 = 1/2
proved
I hope this helps
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