prove that cos4x=1-8 sin^2.cos^2x
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Hey!!!....Here is ur answer
cos4x=cos2 (2x)
=1-2sin^2 2x
=1-2 (2sinx cosx)^2
=1-2 (4sin^x cos^2x)
=1-8 sin^2x.cos^2x
Hope it will help you
cos4x=cos2 (2x)
=1-2sin^2 2x
=1-2 (2sinx cosx)^2
=1-2 (4sin^x cos^2x)
=1-8 sin^2x.cos^2x
Hope it will help you
pragya82:
thanks
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