prove that cosA/ 1+ sinA + 1+ sinA/ cosA= 2 secA
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Answered by
52
lhs= cosA/1+ sinA +1+sinA/cosA
= [(cos^2A)+(1+sinA)^2]/(1+sinA)cosA
=(cos^2A+sin^2A +1+2sinA)/(1+sinA)cosA
=(1+1+2sinA)/(1+sinA)cosA
=(2+2sinA)/(1+sinA)cosA
=2(1+sinA)/(1+sinA)cosA
=2/cosA
=2secA
=rhs
= [(cos^2A)+(1+sinA)^2]/(1+sinA)cosA
=(cos^2A+sin^2A +1+2sinA)/(1+sinA)cosA
=(1+1+2sinA)/(1+sinA)cosA
=(2+2sinA)/(1+sinA)cosA
=2(1+sinA)/(1+sinA)cosA
=2/cosA
=2secA
=rhs
akhilkarishma:
^... wht symbol is thz
plz say
it is power symbol, 3 square = 3^2
exponent can typed use that symbol
Thanx
Answered by
16
= [(cos^2A)+(1+sinA)^2]/(1+sinA)cosA
=(cos^2A+sin^2A +1+2sinA)/(1+sinA)cosA
=(1+1+2sinA)/(1+sinA)cosA
=(2+2sinA)/(1+sinA)cosA
=2(1+sinA)/(1+sinA)cosA
=2/cosA
=2secA
=(cos^2A+sin^2A +1+2sinA)/(1+sinA)cosA
=(1+1+2sinA)/(1+sinA)cosA
=(2+2sinA)/(1+sinA)cosA
=2(1+sinA)/(1+sinA)cosA
=2/cosA
=2secA
^ .....wht this reffr to....plz make me kniw
it means raised to the power
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