Question

Prove that CosA/1-sinA+1-sinA/cosA=2secA

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{cosa}{1 - sina} + \frac{1 - sina}{cosa} \\ \\ = \frac{ {cos}^{2}a + ( {1 - sina})^{2} }{(1 - sina)cosa} \\ \\ = \frac{ {cos}^{2}a + 1 + {sin}^{2} a - 2sina }{(1 -sina)cosa} \\ \\ = \frac{2 - 2sina}{(1 - sina)cosa} \\ \\ = \frac{2}{cosa} \\ \\ = 2seca$