Math, asked by mekadex962, 7 months ago

prove that cosA / 1 - sinA = 2secA - cosA/ 1+sinA

Answers

Answered by jasmine8262

0

cosA/(1-sinA)+cosA(1+sinA)=2secA

cos(1+sinA)+cosA(1-sinA)/(1^2-sin^2A)=2secA

cosA(1+sinA+1-sinA)/cos^2A=2secA

2/cosA=2secA

2secA=2secA

Hence proved

Answered by samueljonathany

0

Answer:

L.H.S.

1+sinA

cosA

+

cosA

1+sinA

=

cosA(1+sinA)

cos

2

A+(1+sinA)

2

=

cosA(1+sinA)

cos

2

A+1+sin

2

A+2sinA

=

cosA(1+sinA)

2+2sinA

=

cosA

2

=2secA = R.H.S.

Step-by-step explanation:

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