Question

prove that cosA/1+sinA+tanA=secA​

Answer 1

Answer:-

=>cosA/1+sin A+tan A

=>cos A/1+sin A + sin A/ cos A [tan A=sin A/cos A ]

=>cos ²A +sin A + sin ² A/ (1+ sin A) cos A

=>1+sin A/(1+ sin A) cos A

=>1/cos A

=>sec A