Prove that cosA × cot A÷ (1-sin A) = 1+cosec A
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Step-by-step explanation:
(cosA * cotA/1 - sinA) ----- (1)
Solve numerator part 1st and then denominator next.
Numerator :
cosA * cotA
=> cosA * (cosA/sinA)
=> cos²A/sinA
=> (1 - sin²A)/sinA
Place Value in (1), it will become
=> (1 - sin²A)/sinA(1 - sinA)
=> (1 - sinA)(1 + sinA)/sinA(1 - sinA)
=> 1 + sinA/sinA
=> (1/sinA) + (sinA/sinA)
=> cosecA + 1
#Hope my answer help you
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