Prove that:-
CosA.sinA=tanA/1+tan2 A
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Answer:
THE QUESTION IS ACTUALLY
Prove that:
(1+tan
2
A)
2
tanA
+
(1+cot
2
A)
2
cotA
=sinAcosA
Step-by-step explanation:
LHS=
(1+tan
2
A)
2
tanA
+
(1+cot
2
A)
2
cotA
(sec
2
A)
2
tanA
+
(cosec
2
A)
2
cotA
=
cos
4
A
1
cosA
sinA
+
sin
4
A
1
sinA
cosA
=sinAcos
3
A+cosAsin
3
A
=sinAcosA[sin
2
A+cos
2
A]
=sinAcosA=RHS
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