Question

Prove that:cosec^4-cosec^2=cot^4A+cot^2A

Answer 1

Lhs = cosex^4A-cosec^2A
=(1+cot^2A)^2 - (1+cot^2A)
[Putting 1+cot ^2A=cosec^2A]
=1+cot^4A+2cot^2A-1-cot^2A
[(a+b)^2=a^2+b^2+2an;]
= cot ^4A+2cot^A-cot^2A
=cot^4A+cot^2A
Therefore, Lhs =rhs .. hence proved

Answer 2

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