PROVE THAT : cosecA+cotA=1÷cosecA-cotA
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Answered by
25
Hey Friend :-)
Here is your answer
=> 1 / (cosecA - cotA) . . . . . . . . . . .multiply top & bottom by (cosecA + cotA)
=> (cosecA + cotA) /(cosec^2A - cot^2A) . . . . . . .use cosec^2A = 1 + cot^2A
=> (cosecA +cotA) / 1
=> cosecA + cotA
RHS = LHS
Hence, proofed.
Hoping it helps
Thanks :D
Here is your answer
=> 1 / (cosecA - cotA) . . . . . . . . . . .multiply top & bottom by (cosecA + cotA)
=> (cosecA + cotA) /(cosec^2A - cot^2A) . . . . . . .use cosec^2A = 1 + cot^2A
=> (cosecA +cotA) / 1
=> cosecA + cotA
RHS = LHS
Hence, proofed.
Hoping it helps
Thanks :D
sanjay323:
Thank you
Answered by
16
RHS
1 / (cosecA - cotA) . . . . . . . . . . .multiply top & bottom by (cosecA + cotA)
(cosecA + cotA) /(cosec^2A - cot^2A) . . . . . . .use cosec^2A = 1 + cot^2A
(cosecA +cotA) / 1
cosecA + cotA
RHS = LHS
QED
HOPE IT HELPS
MARK BRAINLIEST
1 / (cosecA - cotA) . . . . . . . . . . .multiply top & bottom by (cosecA + cotA)
(cosecA + cotA) /(cosec^2A - cot^2A) . . . . . . .use cosec^2A = 1 + cot^2A
(cosecA +cotA) / 1
cosecA + cotA
RHS = LHS
QED
HOPE IT HELPS
MARK BRAINLIEST
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